【剑指Offer】树的子结构 Posted on 2017-05-14 | In Algorithm , 剑指Offer 题目输入两棵二叉树A和B,判断B是不是A的子结构。 实现123456789public class TreeNode { int val = 0; TreeNode left = null; TreeNode right = null; public TreeNode(int val) { this.val = val; }} 123456789101112131415161718192021222324252627public boolean HasSubtree(TreeNode root1, TreeNode root2) { boolean result = false; if (root1 != null && root2 != null){ if (root1.val == root2.val) result = DoesTree1HasTree2(root1, root2); if (result == false) result = HasSubtree(root1.left, root2); if (result == false) result = HasSubtree(root1.right, root2); } return result;}private boolean DoesTree1HasTree2(TreeNode root1, TreeNode root2){ if (root2 == null) return true; else if (root1 == null) return false; else if (root1.val != root2.val) return false; return DoesTree1HasTree2(root1.left, root2.left) && DoesTree1HasTree2(root1.right, root2.right);}